Afood processor packages orange juice in small jars. the weights of the filled jars are approximately normally distributed with a mean of 10.5 ounces and a standard deviation of 0.3 ounce. find the proportion of all jars packaged by this process that have weights that fall above10.95 ounces.

6.68 %.

Step-by-step explanation:

The standardised z-score = ( 10.95 - 10.5) /  0.3

= 1.5.

Looking up the Normal Distribution tables ( area to the left) 1.5 corresponds to  0.93319 so for   a  weight above 10.95 the proportion is

1 - 0.93319 = 0.06681

= 6.68%.

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step-by-step explanation: