Patrick travels from a to b at an average speed of 8km/h and then he travels from b to c at an average speed of 6 km/h. it is given that patrick travels 26.4 km in 234 minutes for the whole journey. find the distance that patrick travels from a to b.

12 km

Step-by-step explanation:

So the situation is:

8 km/h for X hours

6 km/h for y hours

X * 8 + y * 6 = 26.4

and X + Y = 3.9 hours

Since 234/60 = 3.9 hours

You could write that X = 3.9 - Y

(3.9-Y) * 8 + y * 6 = 26.4

31.2 -8Y +6Y = 26.4

-2Y = -4.8

Y = 2.4 hours

X = 3.9-2.4 = 1.5 hours

So 1.5 * 8 = 12 km

AB = 12km

Step-by-step explanation:

From the question we can get the following information,

The whole trip is 26.4 km and 3.9 hours (), and we can form the following two equations.

  and

Where X is distance between A and B, and Y is distance between B and C. We can solve the first equation for X and plug X into the second equation.

 ........   and we can plug it into the the second equation and solve for y

Now we can plug in y to the first equation to solve for x

Finally, we can multiplay 8km/h by 1.5 hours to find the distance from A to B

6hryt%4578855

{3 + i, 3 - i, 3, -1}

step-by-step explanation: