Find lim x→0 1 − cos x x2 . (b) use your answer to part (a) to derive the approximation cos x ≈ 1 − 1 2 x2 for x near 0. for x ≈ 0. 1 − cos x x2 ≈ 1 2 1 − cos x ≈ x2 2 cos x ≈ 1 − (c) use your answer to part (b) to approximate cos(0.08). (d) use a calculator to approximate cos(0.08) to four decimal places. compare the result with part (c). the result from part (c) is the same to four decimal places. the result from part (c) is not the same to four decimal places.

Vhich expression is equivalent to 6(3x + 4)? 9x + 418 x + 2418x + 49x + 10 i might ! i really do hope u see this and answer it

Choose the point slope form of the equation below that represents the like that passes through the points (-6,4) and (2, 0)

To find the extreme values of a function f(x.y) on a curve x-x(t), y y(t), treat f as a function of the single variable t and use the chain rule to find where df/dt is zero. in any other single-variable case, the extreme values of f are then found among the values at the critical points (points where df/dt is zero or fails to exist), and endpoints of the parameter domain. find the absolute maximum and minimum values of the following function on the given curves. use the parametric equations x=2cos t, y 2 sin t functions: curves: i) the semicircle x4,y20 i) the quarter circle x2+y-4, x20, y20 b, g(x,y)=xy