Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in, and a standard deviation given by sigma equals 2.5 in. (a) if 1 woman is randomly selected, find the probability that her height is less than 63 in. (b) if 35 women are randomly selected, find the probability that they have a mean height less than 63 in. (a) the probability is approximately nothing. (round to four decimal places as needed.) (b) the probability is approximately nothing. (round to four decimal places as needed.)

a) The probability is approximately = 0.5793

b) The probability is approximately=0.8810

Step-by-step explanation:

Given : Mean :

Standard deviation :

a) The formula for z -score :

Sample size = 1

For x= 63 in. ,

The p-value =

Thus, the probability is approximately = 0.5793

b)  Sample size = 35

For x= 63 ,

The p-value =

Thus , the probability is approximately=0.8810.

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13

none cuz there are no "following statements" regarding the question

step-by-step explanation: