An aircraft seam requires 28 rivets. the seam will have to be reworked if any of these rivets is defective. suppose rivets are defective independently of one another, each with the same probability. (round your answers to four decimal places.) (a) if 17% of all seams need reworking, what is the probability that a rivet is defective? .0066 (b) how small should the probability of a defective rivet be to ensure that only 9% of all seams need reworking? .0034

10 you would take 50/ .2

step-by-step explanation:

the real question is why is this guys last name heavyfoot

step-by-step explanation:

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0