![\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] ~\dotfill\\\\ f(x)=-x^2\implies y = -(x-\stackrel{h}{0})^2+\stackrel{k}{0}\qquad \qquad \stackrel{\textit{vertex}}{(0,0)}](/tpl/images/0067/6882/707b9.png)
Which function has a vertex at the origin
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