Match each spherical volume to the largest cross sectional area of that sphere

Part 1) ------>

Part 2) ------>

Part 3) ------>

Part 4) ------>

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

The area of the circle is equal to

so

Solve for r

Find the volume of the sphere

The volume of the sphere is

For

substitute

Part 2) we have

The area of the circle is equal to

so

Solve for r

Find the volume of the sphere

The volume of the sphere is

For

substitute

Part 3) we have

The area of the circle is equal to

so

Solve for r

Find the volume of the sphere

The volume of the sphere is

For

substitute

Part 4) we have

The area of the circle is equal to

so

Solve for r

Find the volume of the sphere

The volume of the sphere is

For

substitute

The above answer is correct.

Step-by-step explanation: I got this right on Edmentum.

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

wholesale price is the initial price before markup. retail price comes after the markup.

a price of 8 bucks that's marked up by 100%   is

formula: initial price + (percent markup in fraction/decimal)(initial price)

8+(1)(8)

8+8

16

retail price is $16.