Apopulation of 1,000 bacteria is treated with a medicine and begins to die 5% each hour. how can the bacteria population be determined after a number of hours, ℎ?

a. (ℎ)=0.95(ℎ+1,000)

b. (ℎ)=1,000·ℎ^0.95

c. (ℎ)=0.95ℎ+1,000

d. (ℎ)=1,000·0.95^ℎ

Step-by-step explanation:

is an exponential equation where A is the beginning amount and B is the rate that the population grows or dies.

So we start with 1000 bacteria, they are giving us A.

The bacteria population is decreasing because they are dying 5% each hour.

So that is after the first hour we have 1000-.05(1000) or 1000(1)-1000(.05)=1000(1-.05)=1000(.95).

We will keep multiplying by .95 per hour. 0.95 is the repeated factor.

That is the function is .

If you let h=0 which means 0 hours has happened, you will see the bacteria is 1000 as desired. 1000(.95)^0=1000(1)=1000.

the answer is 200

step-by-step explanation:

the way the question is worded, it seems to imply the $264 interest is simple interest, not compound interest.

the simple interest for 2 years is $264; the simple interest for 1 year is $132.

$132 interest on a $600 investment means an interest rate of (132/600)*100 = 22%.

the value of $200 at 22% interest compounded annually for three years is

200%281.22%29%5e3

the amount of interest is that value, minus the original $200.

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step-by-step explanation: