Encode the message
"jj sylvesterjj sylvester"
using matrix a. remember to partition the numerical message into groups of two. a=left bracket start 2 x 2 matrix 1st row 1st column 1 2nd column 2 2nd row 1st column 1 2nd column 3 end matrix right bracket
1 2
1 3
the coded message is:    

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

one set of data has more variation than the other. hope this !

b, 20 yards

step-by-step explanation:

1/8 is left? add a bit more info plz