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given parallelogram abcd, diagonals ac and bd intersect at point e. ae = 2x, be=y+10, ce=x+2 and de=4y - 8. find the length of bd. a.) 16 b.) 32 c.) 18 d.) 6

  B.)  32

Step-by-step explanation:

The diagonals of a parallelogram bisect each other, so ...

  BE = DE

  y+10 = 4y - 8 . . . substitute the given expressions

  18 = 3y . . . . . . . . add 8-y

  6 = y . . . . . . . . . . divide by 3

Then BE = y+10 = 16 and ...

  BD = 2×BE = 2×16

  BD = 32

B.) 32

Step-by-step explanation:

Given parallelogram ABCD, diagonals AC and BD intersect at point E, AE = 2x, BE=y+10, CE=x+2 and DE=4y - 8, the length of BD is 32.

BD = 2×BE = 2×16

3x + 18 = 147°

step-by-step explanation:

3x + 18 = 147°, because the value of the central angle is equal to the value of the arc formed by it.

i hope i you.