Dave wants to purchase 25 pounds of party mix for a total of ? $60. to obtain the? mixture, he will mix nuts that cost ? $4 per pound with pretzels that cost ? $2 per pound. how many pounds of each type and mix should he? use?

5 pounds of nuts and 20 pounds of pretzels

Step-by-step explanation:

Let

x > the number of pounds of nuts

y > the number of pounds of pretzels

we know that

x+y=25

x=25-y > equation A

4x+2y=60 ---> equation B

Solve the system by substitution

Substitute equation A in equation B and solve for y

4(25-y)+2y=60

100-4y+2y=60

4y-2y=100-60

2y=40

y=20 pounds of pretzels

Find the value of x

x=25-y

x=25-20=5 pounds of nuts

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068