Mathematics, 10.07.2019 18:20 emilylunaa

Drag the tiles to the correct boxes to complete the pairs. not all tiles will be used.
match each graph with the function it represents.

Drag the tiles to the correct boxes to complete the pairs. not all tiles will be used. match e

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Answer from: michelemosbahiow6yya

Graph A → y=√x.

Graph B → y=(√x) - 1.

Graph C → y=√(x-1).

Graph D → y= -√x.

Graph E → y= -√(x-1)

Step-by-step explanation:

The graph 'A' intercepts the y-axis at (0, 0). Therefore it belongs to the function y=√x.

The graph 'D' is exactly the same graph 'A' but reflected across the x-axis. Therefore, it belongs to the function y=-√x.

The function 'C' is exactly the same function y=√x but translated one unit to the right, therefore, the solution function is y=√(x-1)

The graph 'E' is exactly the same graph 'C' but reflected across the x-axis, therefore the function is: y= -√(x-1)

In the options you have two times the function y=√x. I assume that's a mistake. The graph 'B' corresponds to y = (√x) - 1

Answer from: macylen3900

Part 1) $f(x)=\sqrt{x-1}$ -----> Graph C

Part 2) $g(x)=-\sqrt{x}$ ----> Graph D

Part 3) $h(x)=\sqrt{x}$ -----> Graph A

Part 4) $j(x)=-\sqrt{x-1}$ ---> Graph E

Step-by-step explanation:

Part 1) we have

$f(x)=\sqrt{x-1}$

Find the domain of the function

The radicand must be positive

$x-1\geq 0$

Solve for x

$x\geq 1$

The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

Find the range

For x=1

$f(1)=\sqrt{1-1}=0$

The range is the interval ----> [0,∞)

All real numbers greater than or equal to 0

therefore

The function represent Graph C

Part 2) we have

$g(x)=-\sqrt{x}$

Find the domain of the function

The radicand must be positive

$x\geq 0$

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

Find the range

For x=0

$f(0)=-\sqrt{0}=0$

The range is the interval ----> (-∞,0]

All real numbers less than or equal to 0

therefore

The function represent Graph D

Part 3) we have

$h(x)=\sqrt{x}$

Find the domain of the function

The radicand must be positive

$x\geq 0$

Solve for x

$x\geq 0$

The domain is the interval -----> [0,∞)

All real numbers greater than or equal to 0

Find the range

For x=0

$f(0)=\sqrt{0}=0$

The range is the interval ----> [0,∞)

All real numbers greater than or equal to 0

therefore

The function represent Graph A

Part 4) we have

$j(x)=-\sqrt{x-1}$

Find the domain of the function

The radicand must be positive

$x-1\geq 0$

Solve for x

$x\geq 1$

The domain is the interval -----> [1,∞)

All real numbers greater than or equal to 1

Find the range

For x=1

$f(1)=-\sqrt{1-1}=0$

The range is the interval ----> (-∞,0]

All real numbers less than or equal to 0

therefore

The function represent Graph E

Answer from: Quest

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Answer from: Quest

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