Water from a hose is sprayed on a fire burning at a height of 10 m up the side of a wall. if the function h(x) = -0.15t^2 + 3x, where x is the horizontal distance from the fire, in metres, models the height of the water, h(x), also in metres. how far back does the firefighter have to stand in order to put out the fire?
answer asap will give brainliest

  4.2 or 15.8 metres

Step-by-step explanation:

We assume your model for the height of the water stream is supposed to be ...

  h(x) = -0.15x^2 +3x

This will have a value of 10 when ...

  -0.15x^2 +3x = 10

  .15x^2 -3x +10 = 0 . . . . . subtract the left side to get standard form

For a quadratic equation of the form ...

  ax² +bx +c = 0

The solutions are given by the "quadratic formula:"

The above equation matches the template with a=0.15, b=-3, c=10. Putting these values into the formula gives ...

  x ≈ 4.2 or 15.8

The firefighter can stand at 4.2 metres or 15.8 metres from the fire to get the water to arrive at the building 10 metres up.

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,

b is the right answer