Aparabola with vertex (1,5) and y-intercept
(0,2) crosses the x-axis in two places. one x-
intercept is at (-0.29,0). find the other x-
intercept. separate the values with a comma.

So the other x-intercept we are looking for is (2.29 , 0).

Step-by-step explanation:

The equation for a parabola in vertex form is

where (h,k) is the vertex.

So we are given (h,k)=(1,5) so let's plug that in.  This gives us the following equation for our parabola:

.

Now we need to find . Let's find by using another point (x,y) given.  We are given that (0,2) is on our parabola. So when x is 0, y is 2.

This gives us the equation:

So our parabola in vertex form looks like this:

Now we are asked to find the x-intercepts.

You can find the x-intercepts by setting y equal to 0 and solving for x.

So let's do that:

Subtract 5 on both sides:

Divide both sides by -3:

Take the square root of both sides:

Add 1 on both sides:

So the two solutions in exact form are

Putting both into calculator (separately) gives:

So the other x-intercept we are looking for is (2.29 , 0).

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

17 1/3

step-by-step explanation: