What is the probability of the next elk caught in the park being unmarked? write the probability as a fraction, a decimal number, and a percentage.

There are a total of 5,625 Elk in the park and 225 of them are marked.

225 / 5625 = 0.04 = 4% are marked.

This means 96% ( 100-4 = 96) are not marked.

This would be the probability of an elk being unmarked.

As a fraction this would be 96/100 which reduces to 24/25

As a decimal it would be 0.96

As a percent it is 96%

$6.42

step-by-step explanation:

3,6 and 7.

step-by-step explanation:

a) unit place of 37 is 7

so the unit place of cube of 37 will be

7³= 343=3

the answer is 3.

b) unit place of 56 is 6, so the unit place of cube of 56 will be

6³= 216=6

the answer is 6.

c) unit place of 133 is 3, so the unit place of cube of 133 will be

3³= 27= 7.

the answer is 7.