![\bf tan(39^o)=\cfrac{\stackrel{opposite}{x}}{\stackrel{adjacent}{8}}\implies 8\cdot tan(39^o)=x\implies 6.48\approx x \\\\[-0.35em] ~\dotfill\\\\ \cfrac{sin(39^o)}{x}=\cfrac{sin(51^o)}{8}\implies \cfrac{8\cdot sin(39^o)}{sin(51^o)}=x\implies 6.48\approx x](/tpl/images/0079/3652/1a19e.png)
Why did i get different answers to find x?
the first one i used soh cah toa and the second on...
Mathematics, 12.07.2019 02:40 elizabethluna058
Why did i get different answers to find x?
the first one i used soh cah toa and the second one i used laws of sines
Answers: 1
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