robin is giving toy cars to some children at a carnival. he has 2 black toy cars, 7 blue toy cars, and 3 yellow toy cars. if robin selects a toy car randomly without looking, what is the probability that he will give a yellow toy car to the first child and then a blue toy car to the second child? 3 over 12 multiplied by 7 over 11 is equal to 21 over 132 3 over 12 multiplied by 7 over 12 is equal to 21 over 144 3 over 12 plus 7 over 11 is equal to 117 over 132 3 over 12 plus 7 over 12 is equal to 10 over 12

Choice A

3 over 12 multiplied by 7 over 11

(3/12) * (7/11)

Explanation:

There are 3 yellow cars out of 2+7+3 = 12 total. The probability of selecting yellow is therefore 3/12. We can reduce this, but the answer choices decide not to, so we'll do the same.

After picking a yellow car, we have 12-1 = 11 left over. The amount of blue cars do not go down (because we haven't selected it yet). There are 7 blue cars out of the 11 total, so the probability of picking blue for this case is 7/11

Multiply the two fractions to get (3/12)*(7/11) which is a shorthand way of writing "3 over 12 multiplied by 7 over 11".

50-38=12

step-by-step explanation:

dont think so

step-by-step explanation: