a ball is thrown vertically upward. after t seconds, its height h (in feet) is given by the function h(t) = 112t -16t^2 . after how long will it reach its maximum height?
do not round your answer.

After

Step-by-step explanation:

Knowing that after "t" seconds, its height "h" in feet is given by the function:

The maximum height is the y-coordinate of the vertex of the parabola. Then, we can use the following formula to find the corresponding value of "t" (which is the x-coordinate of the vertex):

In this case:

Substituting values, we get that the ball will reach the maximum height after:

1/3 + 1/5 = 8/15.

step-by-step explanation:

hope it