a ball is thrown vertically upward. after t seconds, its height h (in feet) is given by the function h(t) = 52t - 16t^2 . what is the maximum height that the ball will reach?
do not round your answer.

42.25 feet

Step-by-step explanation:

We know that after "t" seconds, its height "h" in feet is given by this function:

The maximum height is the y-coordinate of the vertex of the parabola. Then, we can use the following formula to find the corresponding value of "t" (which is the x-coordinate of the vertex):

In this case:

Substituting values, we get :

Substituting this value into the function to find the maximum height the ball will reach, we get:

42.25 feet

Step-by-step explanation:

The maximum of a quadratic can be found by finding the vertex of the parabola that the quadratic creates visually on a graph.

So first step to find the maximum height is to find the x-coordinate of the vertex.

After you find the x-coordinate of the vertex, you will want to find the y that corresponds by using the given equation, . The y-coordinate we will get will be the maximum height.

Let's start.

The x-coordinate of the vertex is .

compare to .

We have that .

Let's plug into   with those values.

with

.

The vertex's x-coordinate is 13/8.

Now to find the corresponding y-coordinate.

I'm going to just put this in the calculator:

So the maximum is 42.25 feet.

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.