If a polynomial function f(x) has roots 6 and square root of 5, what must also be a root of f(x)?
a. -6
b. square root of -5
c. 6 - square root of 5
d. 6 + square root of 5

-

Step-by-step explanation:

A root with square root or under root is only obtained when we take the square root of both sides. Remember that when we take a square root, there are two possible answers:

For example, for the equation:

If we take the square root of both sides, the answers will be:

Only getting one solution with square root is not possible. Solutions with square root always occur in pairs.

For given case, the roots are 6 and . Therefore, the 3rd root of the polynomial function f(x) had to be -

It seems you made error while writing option B, it should be - square root of 5.

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step-by-step explanation:

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

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m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0