The number n = 100 + 100^2 + 100^3 + + 100^n . find the least possible value of n such that the number n is divisible by 11. need quickly! !

  n = 11

Step-by-step explanation:

100 mod 11 = 1, which is the remainder from division by 11 for each of the terms of the sum. 11 terms of the sum are needed in order to make the remainders add up to a number divisible by 11.

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation:

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step-by-step explanation: