What are the new vertices of triangle  fgh  if the triangle is translated three units to the right?  
            a.  f′ = (–2,–3),  g′ = (0,4),  h′ = (4,–6)    b.  f′ = (–2,–2),  g′ = (0,5),  h′ = (4,–5)    c.  f′ = (–5,–5),  g′ = (–3,3),  h′ = (1,–8)    d.  f′ = (–1,–2),  g′ = (1,5),  h′ = (5,–5)

G'(0,5)

H'(4,-5)

F'(-2,-2)

Step-by-step explanation:

We need to identify the three vertices from the figure on the graph:

G(-3,5)

H(1,-5)

F(-5,-2).

If we translate these points 3 units to right, then that effects the x-coordinates.

So 3 more than -3, is 0.

3 more than 1 is 4.

3 more than -5 is -2.

So the new points are:

G'(0,5)

H'(4,-5)

F'(-2,-2).

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3