The perimeter of δabc is 13 cm. it was dilated to create δa'b'c'. what is the perimeter of δa'b'c'? 13 cm 26 cm 39 cm 52 cm

The answer is 52

Step-by-step explanation:

We need figure out the dilated by doing OB’/OB. 5+15= OB’. OB’ = 20. We already know that OB is 5. We used the substitution property. 20/5 = 4. Now, we got 4 as dilation. 13 cm x 4 = 52 cm. Therefore, our answer is 52

it has changed from the width and the height.

step-by-step explanation:

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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