Factor by grouping 6v^3-14v^2+15v-35

(3v-7)(2v^2+5)

Step-by-step explanation:

To factor 6v^3-14v^2+15v-35 by grouping we are going to try pair to up the pair two terms and also the last two terms. Like this:

(6v^3-14v^2)+(15v-35)

Now from each we factor what we can:

2v^2(3v-7)+5(3v-7)

Now there are two terms: 2v^2(3v-7) and 5(3v-7).

These terms contain a common factor and it is (3v-7).

We are going to factor (3v-7) out like so:

2v^2(3v-7)+5(3v-7)

(3v-7)(2v^2+5)

answer: approximately 206 bones

i hope this u out a branlist and a would be greatly appreciated :

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8