Solve this equation and pick the correct answer
2x^2+5x-7=0
1. x = 7 and x = -2
2. x = -7/2 and x = 1
3. x = -7 and x = 2
4. x = 7/2 and x = -1
i have summer homework and i do not understand this question an anyone explain it to me.

2.  x = -7/2 and x = 1.

Step-by-step explanation:

2x^2 + 5x - 7 = 0

(2x + 7)(x - 1) = 0

x = -7/2, 1.

The answer is 2) x = -7/2 and x = 1

Step-by-step explanation:

You have to use the a•c method.

a^2+b+c

a = 2

b = 5

c = -7

Multiply a(b) = 2(-7)

That'll equal -14. Then find factors of -14 that, when added, will equal to 5 (which is the 'b').

The factors are 7, -2.

Break up the 5x in the equation to -2x and 7x.

It looks like this: 2x^2-2x+7x-7=0

Then group them into two separate groups with parentheses.

It looks like this: (2x^2-2x) + (7x-7)

Then take out the GCF (Greatest Common Factor) for each of the groups.

Like this: 2x(x-1) + 7(x-1)

Then group the 2x and 7 together and only use one of the (x-1).

Like this: (2x+7)(x-1)

Then solve each parentheses by making both equal to zero separately.

Like this: 2x+7 = 0, x-1 = 0

Then solve each one of them for x.

2x+7 = 0

-7 -7

2x = -7

2x/2 = -7/2

x = -7/2

x-1 = 0

+1 +1

x = 1

Then you have your answers: x = -7/2 and x = 1

3. parallelogram

step-by-step explanation:

we turn each of our sides into direction vectors

ab=b-a=(3 - 7, 1 - 0) = (-4, 1)

bc=c-b=(1,6)

cd=d-c=(4,-1)

da=a-d=(-1,-6)

we see how the opposite sides have negated direction vectors; this is characteristic of a parallelogram.   we have congruent sides ab=cd and bc=da with unequal lengths because 1^2+6^2 is different from (-4)^2+1^2.   so it's not a square or a rhombus.  

we check the dot product of direction vectors of adjacent sides.   we have

ab dot bc = -4(1) + 1(6) = 2

that's not zero so the sides are not perpendicular.   we've ruled out rectangle.

the direction vectors indicate two pairs of congruent parallel sides, so we choose parallelogram over trapezoid.

not me

step-by-step explanation:

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