Mathematics, 15.07.2019 08:10 Naviascales1681

What is the equation of the line that goes through the point (6,-1) and is parallel to the line represented by the equation below?
y=-5/6 x+3
a. y= -5/6x + 4
b. y= -5/6x - 6
c. y= -5/6x -4
d. y= -5/6x + 6

Answers: 1

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Answers

Answer from: Joosee4075

$\huge{\boxed{y=-\frac{5}{6} x+4}}$

Parallel lines share the same slope, so the slope of the parallel line in this case must be $-\frac{5}{6}$ .

Point-slope form is y-y_1=m(x-x_1) , where is the slope and (x_1, y_1) is any known point on the line.

Plug in the values. $y-(-1)=-\frac{5}{6} (x-6)$

Simplify and distribute. $y+1=-\frac{5}{6} x+5$

Subtract 1 from both sides. $\boxed{y=-\frac{5}{6} x+4}$

Answer from: Quest

i found two solutions, n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

Answer from: Quest

a. we have two

lines: y = 4-x and

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b. 4-x = 8-x^-1

x 4-x 8-x^-1

-3 7

8.33

-2 6 8.5

-1 5 9

0 4

1 3

2 2

7.5

3 1 7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:

x=-4.236

y = 4-x = 4 – (-4.236)

= 8.236

y = 8-x^-1 = .236)^-1

= 8.236

x=0.236

y = 4-x = 4 – (0.236) = 3.764

y = 8-x^-1 = 8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c. to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x and y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines. the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!

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