Consider a light rod of negligible mass and length l pivoted on a frictionless horizontal bearing at a point o . attached to the end of the rod is a mass m1 . also, a second mass m2 of equal size (i. e., m1 = m2 = m) is attached to the rod (2l/7 from the lower end). what is the moment of inertia i about o?
1. i =(25/16)m l^2
2. i =(85/81)m l^2
3. i =(65/49)m l^2
4. i =(10/9)m l^2
5. i =(58/49)m l^2
6. i =(26/25)m l^2
7. i =(5/4)m l^2
8. i =(13/9)m l^2
9. i =(106/81)m l^2
10. i =(74/49)m l^2

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column

according to egenuity the answer is

step-by-step explanation:

d. 344.22

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right