2points) suppose y=c1ekx+c2e−kxy=c1ekx+c2e−kx where k> 0k> 0 is a constant, and c1c1 and c2c2 are arbitrary constants. find the following. enter c1c1 as c1 and c2c2 as c2. dydx=dydx= (formulas) d2ydx2=d2ydx2= (formulas) rewrite your answer to the previous part in terms of yy. d2ydx2=d2ydx2= (formulas) find the general solution to d2ydx2=16yd2ydx2=16y. enter your answer as an equation y=…y=….

the answer is: the length is 5/6 yards.

give me a or a 5 star rating if this is correct!

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

sorry man i accidentally pressed yes my bad

step-by-step explanation: