Assuming that this tumor occurs as usual, find the mean number of cases in groups of 18 comma 745 children. b. using the unrounded mean from part (a), find the probability that the number of tumor cases in a group of 18 comma 745 children is 0 or 1. c. what is the probability of more than one case? d. does the cluster of four cases appear to be attributable to random chance? why or why not?

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to