If there is a 10% chance of sun tomorrow and 20% chance of wind and no sun what is the probability that it is windy given that it is not sunny? round your answer to the nearest percent

=22%

Step-by-step explanation:

Since we have given two conditions simultaneously that is windy and not sunny. So we will use the concept of conditional probability.

The probability of sunny day= P(sunny)=10%

P(sunny)=10%=0.1

The probability of windy and not sunny=P(windy|not sun)=20%

P(windy|not sun)=20% = 0.2

Now divide the both probabilities:

P(windy|not sun)/P(sunny)

=0.2/[1-0.1]              

{Hence there are 10% chances of sun tomorrow than there are (1 - 0.1) chances of no sun}

If we subtract 1 from 0.1 than it becomes:

=0.2/0.9

=2/9

=0.2222222222

=22%

Hence the probability that it is windy = 22%

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²