The following data represent exam scores in a statistics class taught using traditional lecture and a class taught using a "flipped" classroom. complete parts (a) through (c) below.
traditional 70.3 68.5 79.9 67.6 85.4 79.1 56.0 80.4 79.8 71.7 63.1 70.4 59.1
flipped 75.5 71.7 63.5 71.4 77.7 92.4 79.6 77.5 83.0 69.2 92.6 78.0 76.9
(a) which course has more dispersion in exam scores using the range as the measure of dispersion'?
(b) which course has more dispersion in exam scores using the sample standard deviation as the measure of dispersion?
(c) suppose the score of 59.1 in the traditional course was incorrectly recorded as 591. how does this affect the range?
(d) what property does this illustrate? a. the standard deviation is resistant, but the range is not resistant. b. the range is resistant, but the standard deviation is not resistant. c. both the range and the standard deviation are resistant. d. neither the range nor the standard deviation is resistant.

idk this answer sorry cant on this one.

step-by-step explanation:

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

i suppose it should be (y=2x-5)

step-by-step explanation:

answer: c

substitute in the values.

for a:

f(0) = 0 + 9

f(0) = 9

a is a solution.

for b:

f(7) = 14 + 9

f(7) = 23

b is a solution.

for c:

f (3) = 6 + 9

f(3) = 15

c is not a solution. it's supposed to be 14.

for d:

f(2) = 4 + 9

f(2)= 13

d is a solution.