In the circle , mbc =38 and mad =146
what is m

m<AED = 92°

Step-by-step explanation:

It is given that,

measure of arc BC = 38° therefore m<BDC = 38/2 = 19°

measure of arc AD = 146° therefore m<ACD = 146/2 = 73°

To find the measure of <CED

Consider the ΔCDE

m<D = m<BDC = 19° and

m<C = m<ACD = 73°

By using angle sum property  m<CED can be written as,

m<CED = 180 -( m<D + m<C )

 = 180 - (19 + 73)

 = 180 - 92

= 88°

To find the measure of <AED

<AED  and <CED are linear pair

m<AED + m<CED = 180

m<AED = 180 - m<CED

 = 180 - 88

 = 92°

Therefore m<AED = 92°

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

i belive those are the ones that are under 90 degreese.