(a) w = x^2 + y^2 + 2ixy ;
(b) w = x(x^2 - 3y^2) - iy(3x^2 - y^2) ;
(c) w =
(2(x^2 + y^2) - (x + iy))/
(4(x^2 + y^2) - 4x + 1)

the answer i think is a)

step-by-step explanation:

your answer is the frist one

hop i

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204