4. (5 points) nonhomogeneous matrix equations consider the following nonhomogeneous matrix equation, where a is a square matrix ax = b. and its associated homogeneous version when a is invertible both of these equations will have a unique solution. when a is not invertible, equation (1) will have either no solution or infinitely many solutions, whereas equation (2) will necessarily have infinitely many solutions because the trivial solution, x = 0 is a solution and thus it is impossible to have no solution. suppose a is not invertible, but x, is a solution to (1), and the set b-(x, xo) is a basis for the solution space of (2). then is the general solution to (1) for any scalars c and c because

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

segment bisector

step-by-step explanation:

line segment bisector. definition: a line, ray or segment which cuts another line segment into two equal parts. try this drag one of the orange dots at a or b and note the the line ab always divides the line pq into two equal parts.

mark brainliest!

answer: -0.5 would be the most likley outcome

step-by-step explanation: