Genes a, b and c are linked on a particular chromosome in this order. the distance between a and b is 9.0 map units, while b and c are 30 map units apart. what is the probability of a double crossover if interference in this chromosomal region is 70%?

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation:

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

answer: it is a.,b.,d.

step-by-step explanation:

idk wbu

step-by-step explanation: