The distances (y), in miles, of two cars from their starting points at certain times (x), in hours, are shown by the equations below: car a: y = 52x + 70 car b: y = 54x + 56 after how many hours will the two cars be at the same distance from their starting point and what will that distance be? 6 hours, 420 miles 6 hours, 434 miles 7 hours, 420 miles 7 hours, 434 miles

the answer is ! ?

i think it’s c i believe

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²