Given the geometric sequence where a1 = 4 and the common ratio is 3, what is the domain for n?
a) all integers where n ≥ 1
b) all integers where > 1
c) all integers where n ≥ 4
d) all real numbers

The correct option is A.

Step-by-step explanation:

According to statement a1 = 4 and r = 3. This shows that r is greater than 1.

If r is greater than 1 than it includes integers greater than 1 or equal to 1. It does not include all the real numbers because real numbers include negative numbers also.

If starting value is 4,if we put n=0, then we get 4, but if we put a negative value than we would get a number which is not a part of our sequence. Thus the correct option is All integers where n ≥ 1

step-by-step explanation:

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.