How can i solve this.
given: △pst, m∠s=90°, m∈ segment pt,
segment pm ≅ mt,
mk ⊥ pt
m∠spk/m∠kpm = 5/2
find: m∠p, m∠t, m∠skp, and m∠mkt

m∠P=70°, m∠T=20°, m∠SKP=40°, and m∠MKT=70°.

Step-by-step explanation:

Given information: △PST, m∠S=90°, M∈ segment PT, segment PM ≅ MT, MK ⊥ PT, m∠SPK/m∠KPM = 5/2.

Let the measure of m∠SPK and ∠KPM are 5x° and 2x° respectively.

In triangle PKM and TKM,

               (Common side)

               (MK ⊥ PT)

          (Given)

By SAS postulate,

             (CPCTC)

According to angle sum property, the sum of interior angles of a triangle is 180°.

Use angle sum property in triangle SPT,

The value of x is 10.

Therefore, m∠P=70° and m∠T=20°.

Use angle sum property in triangle SPK.

Therefore the measure of ∠SKP is 40°.

Use angle sum property in triangle MKT.

Therefore, the measure of ∠MKT is 70°.

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.