Question 7 10 points save answer you are spinning a 025 kg mass over your head at the end of a 0 5 m string lif you let go of the string the mass wil sail ofof a tangent at 2 mis what isthe angular momenturm of the spining mass belore you are spinning a 0 25 kg mass over your head at the release? because angular momentum is always conserved, where does the angular momentum go atter release? question 8 10 points save answer

angular moment is 0.25 kg.m²/s

Step-by-step explanation:

given data in question

mass (m) = 0.25 kg

length of string i.e. radius (r) = 0.5 m

velocity = 2 m/s

to find out

angular momentum before mass release

solution

we know angular moment formula i.e.

angular moment = mass × velocity × radius   1

put the value mass velocity and radius in equation 1 we get angular moment i.e.

angular moment = mass × velocity × radius

angular moment = 0.25 × 2 × 0.5

angular moment = 0.25

so the angular moment is 0.25 kg.m²/s before release and 0.25 kg.m²/s after release because angular momentum is always conserved