- brandon has a fish tank that can hold 38 gallons of water.
- on monday (1st day of the month) there were 38 gallons of water in the tank.
- the fish tank loses 0.75 gallons of water on every odd numbered day.
- brandon adds 0.5 gallons of water to the fish tank on days that are multiples of 3
- how much total water will brandon need to add on the last day of the month (31 days in this month) to fill the tank to 38 gallons
- show 2 different ways to solve this problem

im pretty sure its

(8,15)

step-by-step explanation:

144.50

step-by-step explanation:

21.5 x 13.4=288.10 divide by 2

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺

b. ol

step-by-step explanation:

i got the answer right on edg.

congruent: (geometry) (of figures) identical in form; coinciding exactly when superimposed.