How many solutions are there to the equation x1 +x2 +x3 +x4 +x5 = 18, where x1, x2, x3, x4, x5 are non-negative integers, given the follow restrictions: four of the variables must be odd, and the remaining variable (which may be odd or even) yield a remainder of 2 when divided by 3? justify your answer.

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

(x+3)(x+7)

step-by-step explanation:

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation: