The number of yeast cells in a laboratory culture increases rapidly initially but levels off eventually. the population is modeled by the function n = f(t) = a 1 + be−0.8t where t is measured in hours. at time t = 0 the population is 10 cells and is increasing at a rate of 7 cells/hour. find the values of a and b. a = 1 -25 b = 2 -3.5 according to this model, what happens to the yeast population in the long run? the yeast population will grow without bound. the yeast population will stabilize at 80 cells. the yeast population will stabilize at 40 cells. the yeast population will stabilize at 7 cells. the yeast population will shrink to 0 cells.

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?