Consider the quadratic function f(x)=8x2−7x+6. what is the constant of the function?

6 is constant of the function .

Step-by-step explanation:

Given : f(x)=8x²−7x+6.

To find :  What is the constant of the function?

Solution : We have given that  f(x)=8x²−7x+6.

Standard quadratic equation : ax² +bx +c = 0.

Here,

a is the coefficient  of x² and b is the coefficient of x .

c = constant.

Hence on comparing with it standard quadratic equation

Here, 6 is constant.

Therefore, 6 is constant of the function .

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~