if sin o = -sqrt3 over 2 and n < o < 3 pi over 2, what are the values of cos o and tan o?

Step-by-step explanation:

You know that ...

Using what you know about the relationships of these trig functions, you can find ...

  cos(θ)² = 1 - ((-√3)/2)² = 1 - 3/4 = 1/4

  cos(θ) = -1/2 . . . . . negative square root of 1/4

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  tan(θ) = sin(θ)/cos(θ) = ((-√3)/2)/(-1/2)

  tan(θ) = √3

2

step-by-step explanation: