Aramp into a building forms a 7° angle with the ground. if the entry point of the ramp is 6 feet from the building, how many feet long is the ramp? round the solution to the nearest hundredth. 5.33 feet 6.05 feet 7.04 feet 7.96 feet

6.05 ft

Step-by-step explanation:

BC = 6 ft = Entry point of the ramp to building

∠C = 7° = Ramp angle with the ground

AC = Ramp length

∴The ramp is 6.05 ft in length

  6.05 ft

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you that ...

  Cos = Adjacent/Hypotenuse

  cos(7°) = (6 ft)/(ramp length)

  ramp length = (6 ft)/cos(7°)) ≈ 6.05 ft

the answer is 9.8975

explanation:

when you multiply the "39.59" with the 25% it reduces it and shows its final discounted price. hope this !

step-by-step explanation:

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