Anew game is being introduced at the hard rock cafe. a ball is spun around a wheel until it comes to rest in one of many spots. whatever is listed in that spot will be the player's winnings. if the wheel has 9 spots labeled $1, 18 spots labeled $2, and 1 spots labeled $10, how much should a player expect to win on average? round to the nearest cent. your question 5 options: answer

$ 1.96

Step-by-step explanation:

Number of spots with outcome of $1 = 9

Number of spots with outcome of $2 = 18

Number of spots with outcome of $10 = 1

Total number of spots = 28

Probability that ball will land on $1 =

Probability that ball will land on $2 =

Probability that ball will land on $10 =

The amount that player should expect to win on average in equal to expected value of the game. Expected value is calculated as the summation of product of probabilities with their respective outcomes.

i.e. for this case:

Expected Value will be:

This means, on average the player should expect to win $ 1.96

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

i believe the answer is letter c) 8

step-by-step explanation: