What is the function written in vertex form?
f(x) = 3(x + 4)^2 - 6
f(x) = 3(x + 4)^2 - 38
f(x) = 3(x – 4)^2-6
f(x) = 3(x - 4)^2 - 38

The answer in the procedure

Step-by-step explanation:

The question does not present the graph, however it can be answered to help the student solve similar problems.

we know that

The equation of a vertical parabola into vertex form is equal to

where

a is a coefficient

(h,k) is the vertex

If the coefficient a is positive then the parabola open up and the vertex is a minimum

If the coefficient a is negative then the parabola open down and the vertex is a maximum

case A) we have

The vertex is the point (-4,-6)

a=3

therefore

The parabola open up, the vertex is a minimum

case B) we have

The vertex is the point (-4,-38)

a=3

therefore

The parabola open up, the vertex is a minimum

case C) we have

The vertex is the point (4,-6)

a=3

therefore

The parabola open up, the vertex is a minimum

case D) we have

The vertex is the point (4,-38)

a=3

therefore

The parabola open up, the vertex is a minimum

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step-by-step explanation:

t hope this

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