Specifications call for the wall thickness of two-liter polycarbonate bottles to average 4.0 mils. a quality control engineer samples 7 two-liter polycarbonate bottles from a large batch and measures the wall thickness (in mils) in each. the results are: 3.999, 4.037, 4.116, 4.063, 3.969, 3.955, and 4.091. it is desired to test h0 : μ = 4.0 versus h1 : μ = 4.0. a. make a dotplot of the seven values. b. should a student’s t test be used to test h0? if so, perform the test. if not, explain why not. c. measurements are taken of the wall thicknesses of seven bottles of a different type. the measurements this time are: 4.004, 4.225, 3.924, 4.052, 3.975, 3.976, and 4.041. make a dotplot of these values. d. should a student’s t test be used to test h0 : μ = 4.0 versus h1 : μ ≠ 4.0? if so, perform the test. if not, explain why not.

answer:

125 yards

explanation:

75+50=125. that is my answer

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value

i believe your answer is 99.7% of 7-year-old children are between 46.6 inches and 49.5 inches tall.

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: