Engineers want to design seats in commercial aircraft so that they are wide enough to fit 99% of all males. (accommodating 100% of males would require very wide seats that would be much too expensive.) men have hip breadths that are normally distributed with a mean of 14.5 in. and a standard deviation of 0.9 in. find upper p 99. that is, find the hip breadth for men that separates the smallest 99% from the largest 1%.

16.59 inches

Step-by-step explanation:

Mean value = u = 14.5 inches

Standard deviation = = 0.9 in

We need to find the 99th percentile of the given distribution. This can be done by first finding the z value associated with 99th percentile and then using that value to calculate the exact value of hip breadth that lies at 99th percentile

From the z-table, the 99th percentile value is at a z-value of:

z = 2.326

This means 99% of the z-scores are below this value. Now we need to find the equivalent hip breadth for this z-score

The formula to calculate the z score is:

where, x is the hip breadth which is equivalent to this z-score.

Substituting the values we have:

Rounded to 2 decimal places, engineers should design the seats which can fit the hip breadth of upto 16.59 inches to accommodate the 99% of all males.

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.