Problem1 a right square frustum is formed by cutting a right square pyramid with a plane parallel to its base. suppose the original pyramid has base length 6 and height 9. and that plane cutting the pyramid to form the frustum is 3 units from the base of pyramid. what is the volume, in cubic units, of the right square frustum that is cut off by this plane?

Volume of the frustum is 76 unit³

Step-by-step explanation:

From the figure attached we have to calculate the volume of the frustum formed by cutting off a square pyramid from the top.

Volume of the frustum =

Since ΔAPO' and ΔAOQ are similar so

O'P = units

Therefore, side MN = 2× O'P = 4 units

Now we put these values in the formula

Volume of the frustum =

=

=

=

= 76 unit³

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it